Calculus I > Precalculus Review

Sine and cosine function

The function  $ y = \sin x$ and $ y = \cos x$ are respectively called sine and cosine function. The domain of both functions is $ {D = (-\infty, \infty)}$, and their range is $ R = [-1,1]$. But the sine function is odd: $ \sin(-x) = - \sin x$, and the cosine function is even: $ \cos(-x) = \cos x$.

  (S) $ y = \sin x$
\includegraphics{lec10a.ps} \includegraphics{lec10b.ps}
  (C) $ y = \cos x$
  \includegraphics{lec10c.ps}

Periodic function. A function $ f$ is said to be periodic if it satisfies $ f(x + c) = f(x)$ for every $ x$ with some constant value $ c$. The least such positive value $ c = c_0$ for which $ f(x + c) = f(x)$ holds is called the period of $ f$. The sine function and the cosine function are periodic, and both have the period of $ 2 \pi$: $ \sin(x + 2\pi) = \sin x$ and $ \cos(x + 2\pi) = \cos x$. Moreover, we can observe that $ \sin(x + 2\pi n) = \sin x$ and $ \cos(x + 2\pi n) = \cos x$ for any integer $ n$. The immediate application is to find the coordinate $ (\cos\theta, \sin\theta) = (\cos\theta_R, \sin\theta_R)$ on the unit circle by using the “reference angle $ \theta_R$” (the acute angle between the terminal side of the original angle $ \theta$ and the $ x$-axis). The value $ \pi$ is not the period for the sine and the cosine functions, but rather it gives the phase shift: $ \sin(x + \pi) = -\sin x$ and $ \cos(x + \pi) = -\cos x$.


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