Generating...                               part2_n16

  1. If $x>0$ and $y>0$, then $\sqrt{ 64 \sqrt{ 16 x^{ 8} y^{ 6}}}$ =

    $\displaystyle 16\,x^2\,y^{{{3}\over{2}}}$

    $\displaystyle 16\,x^4\,y^4$

    $\displaystyle 16\,x^2\,y^{{{3}\over{2}}}$

    $\displaystyle 2\,x^4\,y^3$

    $\displaystyle 32\,x^2\,y^{{{3}\over{2}}}$

  2. The graph of $\displaystyle y=4\,x-2\,x^2$ is symmetric with respect to the line

    x = 1

    x = 2

    x = −1

    y = −1

    y = 1

  3. The inequality $\displaystyle x^2-8\,x<9$ is equivalent to

    x <  − 1 or x > 9

    −9 < x < 1

    −8 < x < 1

    −1 < x < 8

    −1 < x < 9

  4. An equation of the line passing through ( 3 , −1 ) having slope $\displaystyle -{{1}\over{4}}$ is

    −4y − x = −1

    4y − x = −1

    −4y − x = 7

    −4y − x = 1

    4y − x = 1

  5. $\displaystyle {{x-2}\over{x^2-9}} \times {{16\,x-48}\over{4\,x-8}} $ = ?

    $\displaystyle {{4}\over{x+3}}$

    $\displaystyle {{4}\over{x^2-9}}$

    $\displaystyle {{4}\over{x-3}}$

    $\displaystyle {{16}\over{x+3}}$

    $\displaystyle {{8}\over{x-3}}$

  6. $\displaystyle \frac{1}{ 2 + \sqrt{13}}$ =

    $\displaystyle \frac{ 2 + \sqrt{13}} { -9} $

    $-2 + \sqrt{13} $

    $\displaystyle \frac{ 2 - \sqrt{13}} { -9} $

    $\displaystyle \frac{ 2 + \sqrt{13}} { 17} $

    $\displaystyle \frac{ 2 - \sqrt{13}} { 17} $

  7. The graph of the system of equations \begin{displaymath}\begin{cases} 4\,x-8\,y=1 \\ [1ex] 24\,y+12\,x=3 \end{cases}\end{displaymath} consists of

    two lines intersecting where $\displaystyle x={{1}\over{4}}$

    one line

    two lines intersecting where $\displaystyle y={{1}\over{4}}$

    two distinct parallel lines

    two lines intersecting where x = 1


Department of Mathematics
Last modified: 2026-09-10